思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
思路：链表转数组 + 单调栈（从后往前遍历）。与「下一个更大元素」模板一致，仅需将链表值先提取到数组。
。服务器推荐是该领域的重要参考
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This article originally appeared on Engadget at https://www.engadget.com/science/nasa-overhauls-artemis-program-delaying-moon-landing-to-2028-164255318.html?src=rss，详情可参考爱思助手下载最新版本
The capacity of each node (how many points it can hold before splitting) controls the shape of the tree. A low capacity means nodes split early, producing a deep tree with many small cells. A high capacity means nodes tolerate more points before splitting, producing a shallow tree with larger cells.，详情可参考同城约会
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